CBSE Class 12 Biology HOTs Principles Of Inheritance And Variation

Please refer to CBSE Class 12 Biology HOTs Principles Of Inheritance And Variation. Download HOTS questions and answers for Class 12 Biology. Read CBSE Class 12 Biology HOTs for Chapter 5 Principles of Inheritance and Variation below and download in pdf. High Order Thinking Skills questions come in exams for Biology in Class 12 and if prepared properly can help you to score more marks. You can refer to more chapter wise Class 12 Biology HOTS Questions with solutions and also get latest topic wise important study material as per NCERT book for Class 12 Biology and all other subjects for free on Studiestoday designed as per latest CBSE, NCERT and KVS syllabus and pattern for Class 12

Chapter 5 Principles of Inheritance and Variation Class 12 Biology HOTS

Class 12 Biology students should refer to the following high order thinking skills questions with answers for Chapter 5 Principles of Inheritance and Variation in Class 12. These HOTS questions with answers for Class 12 Biology will come in exams and help you to score good marks

HOTS Questions Chapter 5 Principles of Inheritance and Variation Class 12 Biology with Answers

 

Q.1. At which stage of meiosis does the segregation of Mendelian factors can be seen?
 
Ans1. Anaphase- I
 
Q.2. Which of the following is a recessive or dominant trait in garden pea?
a) Tall stem b) Wrinkled seeds
c) Green color seed coat d) Constricted pod.
 
Ans2. Dominant trait-tall stem
Recessive trait-winkled seed, green color coat seed constricted pod.
 
Q.3. Mendel followed a definite sequence of steps in making a cross between tall and Dwarf pea plants to study the inheritance of one gene. Mention them in proper order.
 
Ans3. Plant tall and dwarf -removal of anthers [emasculation] from one -transfer of pollen from second to first (pollination) - Syngamy - Seed production - Formation of pod.
 
Q.4. Name a cross whose progenies can easily be analyzed to predict the genotype of the organism under observation ?
 
Ans4. Test cross.
 
Q.5. Turner’s syndrome is a sterile female generally with normal intelligence and known viable monosony in humans. Is the combination ‘44+YO’ is also viable. Justify?
 
Ans5. No, absence of even a single copy of ‘X’ chromosome (lot of important genes) results in nonviability of ‘YO’ combination.
 
Q.6. The genetic disorders can be grouped under two broad categories- Mendelian disorders And chromosomal disorders which one of two can be traced in a family by pedigree chart? Name two such disorders.
 
Ans6. Mendalian inheritance. E.g. - Hemophilia and Colour blindness.
 
Q.7. A mother with blood group ‘O’ has a foetus with blood group ‘A’, father is also ‘A’ If the genes of the both the parents are inherited then the foetus should be a mixture of both the parents i.e. half ‘O’ and half ‘A’. Since the foetus is ‘A’, how can you explain the situation?
 
Ans7. Follow the principle of inheritance and law of dominance with gene for ‘A’ being dominant over gene for ‘O’, get the mono-hybrid cross.
 
Q.8. What is the advantage of presence of sickle allele in the heterozygous condition?
 
Ans8. Sickle allele in heterozygous condition protects the person against malaria (RBC having sickle shaped hemoglobin were readily infected with malarial parasite and with the bursting of such an RBC, parasites present in the sickled cells also die.
 
Q.9. When you will find the percentages of crossing over will be more
a) When linked genes are located close to each other.
b) When linked genes are located far apart from each other.
c) When genes are not linked.
 
Ans9. When genes are not linked.
 
Q.10. What is the name given to the genes present in the different region [Non- -Homologous] of the ‘Y’ chromosomes and what they code for?
 
Ans10. Holandnic genes (holos-whole: andros –male) They code for male traits such as testes.
 
Q.11. A) Draw a pedigree chart of a family consisting of the following members, age given Within brackets: - father [70] is normal, mother [65] is a carrier, one son [40] is Normal, second son [37] is affected (sufferer). One daughter (33) is normal (non - Carrier), second daughter (30) is normal (carrier).
 
       b)If no daughter in the above family could be born as affected for this trait , work out in a punnet square to find out if this trait could be phenylketonuria and conclude by saying yes or no . [You can use the letters ‘A’ and ‘a’ for the dominant and recessive allele of this gene respectively].
 
Ans11. (a) Carrier may be indicated by dots or written carrier .(Ignore the sequence)
           (b) Phenylketonuria is an autosomal recessive disease, mother is carrier ‘Aa’, father normal ‘AA’. No (aa) produced. No phenylketounria
 
Q.12. Given below is a diagrammatic sketch of the hand of a person.
CBSE_Class_12_Biology_Inheritance_&_Variation_1
a) Name or mention the genetic feature.
b) Make a pedigree of the character to mention its inheritance? What do the circles and squares in the chart represent respectively?
c) Is it a sex linked character? Give reason in support of your answer.
 
Ans12 (a) Polydactyly 11 fingers
     (b) Circles –females  Squares –male
     (c) No both male and female are showing it.
 
Q.13. The genes for haemophilia are located on chromosome of humans. It is normally impossible for a haemophilic father to pass the gene to his son . Why.
 
Ans13. It is ‘X’ linked disorder and the father passes his only ‘X’ chromosomes carrying haemophilic gene to his daughter and not to the son (who receives ‘Y’ chromosome).
 
Q.14. In sexually reproducing organisms what is the contribution of the parents to their offspring ½ of their genes or ¼ of their genes ?
 
Ans. 1/2
 
Q.15. Justify the situation that in human beings, sex of the child is determined by father, and not by mother?
 
Ans 15.
CBSE_Class_12_Biology_Inheritance_&_Variation_2
Q.16. Write the sex chromosomes compliment of the following.
(a) Human female & male
(b) Male and Female grasshopper
 
Ans
.CBSE_Class_12_Biology_Inheritance_&_Variation_3
 
 
Important Questions for NCERT Class 12 Biology Principles of Inheritance and Variation
 

Ques. Haploids are able to express both recessive and dominant alleles/mutations because there are
(a) many alleles for each gene
(b) two alleles for each gene
(c) only one allele for each gene in the individual
(d) only one allele in a gene. 

Answer: C

Ques. Experimental verification of the chromosomal theory of inheritance was done by
(a) Mendel
(b) Sutton
(c) Boveri
(d) Morgan. 

Answer: D

Ques. What map unit (centimorgan) is adopted in the construction of genetic maps?
(a) A unit of distance between genes on chromosomes, representing 50% cross over.
(b) A unit of distance between two expressed genes, representing 10% cross over.
(c) A unit of distance between two expressed genes, representing 100% cross over.
(d) A unit of distance between genes on chromosomes, representing 1% cross over.

Answer: D

Ques. The frequency of recombination between gene present on the same chromosome as a measure of the distance between genes was explained by
(a) Sutton Boveri
(b) T.H. Morgan
(c) Gregor J.Mendel
(d) Alfred Sturtevant.

Answer: D

Ques. The mechanism that causes a gene to move from one linkage group to another is called
(a) inversion
(b) duplication
(c) translocation
(d) crossing-over.

Answer: C

Ques. In a test cross involving F1 dihybrid flies, more parental-type offspring were produced than the recombinant-type offspring. This indicates
(a) the two genes are linked and present on the same chromosome
(b) both of the characters are controlled by more than one gene
(c) the two genes are located on two different chromosomes
(d) chromosomes failed to separate during meiosis. 

Answer: A

Ques. The term “linkage” was coined by
(a) G. Mendel
(b) W. Sutton
(c) T.H. Morgan
(d) T. Boveri. 

Answer: C

Ques. The movement of a gene from one linkage group to another is called
(a) translocation
(b) crossing over
(c) inversion
(d) duplication.

Answer: A

Ques. Fruit colour in squash is an example of
(a) recessive epistasis
(b) dominant epistasis
(c) complementary genes
(d) inhibitory genes. 

Answer: B

Ques. Which of the following statements is not true of two genes that show 50% recombination frequency?
(a) The gene show independent assortment.
(b) If the genes are present on the same chromosome, they undergo more than one cross-overs in every meiosis.
(c) The genes may be on different chromosomes.
(d) The genes are tightly linked. 

Answer: D

Ques. When two unrelated individuals or lines are crossed, the performance of F1 hybrid is often superior to both its parents. This phenomenon is called
(a) heterosis
(b) transformation
(c) splicing
(d) metamorphosis.

Answer: A

Ques. Select the correct statement from the ones given below with respect to dihybrid cross.
(a) Tightly linked genes on the same chromosomes show higher recombinations.
(b) Genes far apart on the same chromosome show very few recombinations.
(c) Genes loosely linked on the same chromosome show similar recombinations.
(d) Tightly linked genes on the same chromosome show very few recombinations. 

Answer: D

Ques. A human male produces sperms with the genotypes AB, Ab, aB and ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this person?
(a) AaBB
(b) AABb
(c) AABB
(d) AaBb 

Answer: D

Ques. In Mendel’s experiments with garden pea, round seed shape (RR) was dominant over wrinkled seeds (rr), yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected phenotypes in the F2 generation of the cross RRYY × rryy?
(a) Round seeds with yellow cotyledons, and wrinkled seeds with yellow cotyledons
(b) Only round seeds with green cotyledons
(c) Only wrinkled seeds with yellow cotyledons
(d) Only wrinkled seeds with green cotyledons

Answer: A

Ques. In order to find out the different types of gametes produced by a pea plant having the genotype AaBb it should be crossed to a plant with the genotype
(a) AABB
(b) AaBb
(c) aabb
(d) aaBB. 

Answer: C

Ques. In a plant, red fruit (R) is dominant over yellow fruit (r) and tallness (T) is dominant over shortness (t). If a plant with RRTt genotype is crossed with a plant that is rrtt,
(a) 25% will be tall with red fruit
(b) 50% will be tall with red fruit
(c) 75% will be tall with red fruit
(d) all the offspring will be tall with red fruit.

Answer: B

Ques. Lack of independent assortment of two genes A and
B in fruit fly Drosophila is due to
(a) repulsion
(b) recombination
(c) linkage
(d) crossing over. 

Answer: C

Ques. Two crosses between the same pair of genotypes or phenotypes in which the sources of the gametes are reversed in one cross, is known as
(a) test cross
(b) reciprocal cross
(c) dihybrid cross
(d) reverse cross. 

Answer: B

67. There are three genes a, b, c. Percentage of crossing over between a and b is 20%, b and c is 28% and a and c is 8%. What is the sequence of genes on chromosome?
(a) b, a, c
(b) a, b, c
(c) a, c, b
(d) None of these 

Answer: A

68. Two non-allelic genes produces the new phenotype when present together but fail to do so independently then it is called
(a) epistasis
(b) polygene
(c) non complementary gene
(d) complementary gene. 

Answer: A

Ques. A and B genes are linked. What shall be genotype of progeny in a cross between AB/ab and ab/ab?
(a) AAbb and aabb
(b) AaBb and aabb
(c) AABB and aabb
(d) None of these

Answer: B

Ques. Ratio of complementary genes is
(a) 9 : 3 : 4
(b) 12 : 3 : 1
(c) 9 : 3 : 3 : 4
(d) 9 : 7. 

Answer: D

Ques. Independent assortment of genes does not take place when
(a) genes are located on homologous chromosomes
(b) genes are linked and located on same chromosome
(c) genes are located on non-homogenous chromosome
(d) all of these. 

Answer: B

Ques. Due to the cross between TTRr × ttrr the resultant progenies show what percent of tall, red flowered plants?
(a) 50%
(b) 75%
(c) 25%
(d) 100%

Answer: A

 

Q.1 How will you find the genotype of an organism exhibiting a dominant phenotype trait ?
 
Ans By test cross ,with a homozygous recessive one .
 
Q.2 What is the probability of Haemophilia in the son when a normal homozygous women is married to a Haemophilic man ?
 
Ans 0 %
 
Q.3 Show through a cross all the possibility of the genotypes of the progeny when a man with blood group B marries a women with blood group A, both heterozygous for the trait .
 
Ans Genotypes – IaIb , Ibi ,Iai , ii
 
Q.4 What will be the karyotype of an individual who has developed from the zygote formed by an XX egg fertilized by a Y sperm ?Name the abnormality with which he will be suffering from .
 
Ans 47 chromosome , Klinefelter's syndrome.
 
Q.5 What will be the percentage of gametes ry , formed by an individual with genotype RrYy ?
 
Ans.  ry – 25% .
 
Q.6 The distance between the two strands of DNA is maintained constant ? How it is maintained ?
 
Ans  By base pairing between the two strands that is adenine with thymine with two hydrogen bond and guanine with cytosine with 3 hydrogen bond.
 
Q.7 Fillin the blanks a , b, c and d :
TRAIT                             DOMINANT                        RECESSIVE
Seed shape                        a                                     wrinkled
Flower position             Axillary                                     b
Pod shape                          c                                 constricted
Pod colour                       Green                                     d
 
Ans a -- round , b –terminal ,c -- inflated , d --yellow
 
Q.8 What is the method of finding the genotype of an organism exhibiting a dominant phenotype trait ? Explain.
 
Ans. Test cross.In the cross ,if the individual is homozygous dominant ,all the individuals in the progeny will be dominant. If the individual is he and recessive trait in the ratio of 1:1. terozygous, the progeny will show both dominant.
 
 
 
Important Questions for NCERT Class 12 Biology Principles of Inheritance and Variation
 

Ques. A gene pair hides the effect of another gene. The phenomenon is called
(a) dominance
(b) segregation
(c) epistasis
(d) mutation. 

Answer: C

Ques. If Mendel had studied the seven traits using a plant with 12 chromosomes instead of 14, in what way would his interpretation have been different?
(a) He would not have discovered the law of independent assortment.
(b) He would have discovered sex linkage.
(c) He could have mapped the chromosome.
(d) He would have discovered blending or incomplete dominance. 

Answer: A

Ques. Crossing over in diploid organism is responsible for
(a) segregation of alleles
(b) recombination of linked alleles
(c) dominance of genes
(d) linkage between genes. 

Answer: B

Ques. A fruit fly is heterozygous for sex-linked genes, when mated with normal female fruit fly, the males specific chromosome will enter egg cell in the proportion
(a) 3 : 1
(b) 7 : 1
(c) 1 : 1
(d) 2 : 1. 

Answer: C

Ques. When two dominant independently assorting genes react with each other, they are called
(a) collaborative genes
(b) complementary genes
(c) duplicate genes
(d) supplementary genes.

Answer: B

Ques. When two genetic loci produce identical phenotypes in cis and trans position, they are considered to be
(a) multiple alleles
(b) the parts of same gene
(c) pseudoalleles
(d) different genes. 

Answer: C

Ques. The phenomenon, in which an allele of one gene suppresses the activity of an allele of another gene, is known as
(a) epistasis
(b) dominance
(c) suppression
(d) inactivation. 

Answer: A

Ques. Which of the following is suitable for experiment on linkage?
(a) aaBB × aaBB
(b) AABB × aabb
(c) AaBb × AaBb
(d) AAbb × AaBB

Answer: B

Ques. Two dominant nonallelic genes are 50 map units apart. The linkage is
(a) cis type
(b) trans type
(c) complete
(d) absent/incomplete.

Answer: D

Ques. Mendel studied inheritance of seven pairs of traits in pea which can have 21 possible combinations. If you are told that in one of these combinations, independent assortment is not observed in later studies, your reaction will be
(a) independent assortment principle may be wrong
(b) Mendel might not have studied all the combinations
(c) it is impossible
(d) later studies may be wrong. 

Answer: B

Ques. In a cross between AABB × aabb, the ratio of F2 genotypes between AABB, AaBB, Aabb and aabb would be
(a) 9 : 3 : 3 : 1
(b) 2 : 1 : 1 : 2
(c) 1 : 2 : 2 : 1
(d) 7 : 5 : 3 : 1. 

Answer: C

Ques. Segregation of Mendelian factors (no linkage, no crossing over) occurs during
(a) anaphase I
(b) anaphase II
(c) diplotene
(d) metaphase I. 

Answer: A

Ques. The allele which is unable to express its effect in the presence of another is called
(a) codominant
(b) supplementary
(c) complementary
(d) recessive. 

Answer: D

Ques. Cross between AaBB and aaBB will form
(a) 1AaBB : 1aaBB
(b) all AaBB
(c) 3AaBB : 1aaBB
(d) 1AaBB : 3aaBB.

Answer: A

Ques. In a genetic cross having recessive epistasis, F2 phenotypic ratio would be
(a) 9 : 6 : 1
(b) 15 : 1
(c) 9 : 3 : 4
(d) 12 : 3 : 1.

Answer: C

Ques. Bateson used the terms coupling and repulsion for linkage and crossing over. Name the correct parental of coupling type alongwith its cross over or repulsion.
(a) Coupling AABB, aabb; Repulsion AABB, aabb
(b) Coupling AAbb, aaBB; Repulsion AaBb, aabb
(c) Coupling aaBB, aabb; Repulsion AABB, aabb
(d) Coupling AABB, aabb; Repulsion AAbb, aaBB

Answer: D

Ques. Segregation of Mendelian factor (Aa) occurs during
(a) diplotene
(b) anaphase I
(c) zygotene/pachytene
(d) anaphase II. 

Answer: B

Ques. Two linked genes a and b show 20% recombination. the individuals of a dihybrid cross between ++/++ × ab/ab shall show gametes
(a) ++ : 80 : : ab : 20
(b) ++ : 50 : : ab : 50
(c) ++ : 40 : : ab : 40 : : + a : 10 : : + b : 10
(d) ++ : 30 : : ab : 30 : : + a : 20 : : + b : 20. 

Answer: C

Ques. Which of the following characteristics represent ‘inheritance of blood groups’ in humans?
(i) Dominance
(ii) Co-dominance
(iii) Multiple allele
(iv) Incomplete dominance
(v) Polygenic inheritance
(a) (ii), (iii) and (v) (b) (i), (ii) and (iii)
(c) (ii), (iv) and (v) (d) (i), (iii) and (v)

Answer: B

Ques. Inheritance of skin colour in humans is an example of
(a) point mutation
(b) polygenic inheritance
(c) codominance
(d) chromosomal aberration. 

Answer: B

Ques. How many different kinds of gametes will be produced by a plant having the genotype AABbCC?
(a) Two
(b) Three
(c) Four
(d) Nine 

Answer: A

Ques. Which one of the following is an example of polygenic inheritance?
(a) Skin colour in humans
(b) Flower colour in Mirabilis jalapa
(c) Production of male honeybee
(d) Pod shape in garden pea 

Answer: A

Ques. On selfing a plant of F1-generation with genotype “AABbCC”, the genotypic ratio in F2-generation will be
(a) 3 : 1
(b) 1 : 1
(c) 9 : 3 : 3 : 1
(d) 27 : 9 : 9 : 9 : 3 : 3 : 3 : 1. 

Answer: A

Ques. In human beings, multiple genes are involved in the inheritance of
(a) sickle-cell anaemia
(b) skin colour
(c) colour blindness
(d) phenylketonuria.

Answer: B

 

1) The following table shows the genotypes for ABO blood grouping and their phenotypes .

Fill in the gaps left in the table.. 

class_12_Biology__Hots_4

2)A homozygous green seeded plant is crossed with yellow seeded plant. The progeny obtained was half yellow seeded and half green seeded . 

 

i) Write the genotype of yellow seeded progeny.

 

ii)Write the technical name of the cross.

 

3 MARKS

 

1) In the following pedigree chart, state if the trait is autosomal dominant, autosomal recessive or sex linked. Give a reason for your answer 

class_12_Biology__Hots_5

2) A man with blood group A married a woman with B group, they have a son with AB blood group and a daughter with blood group O, work out the possibility of inheritance with the help of a Punnet square. 

 

3) In a hybrid cross the following recombination frequencies are observed, i.e. 10%, 22% and 6% of recombinants.

 

i)How is this recombinant percentage related to the loci of the gene responsible for recombinants.

 

ii) Which phenomenon is associated with this?
CBSE_Class_12_Biology_Inheritance_Variation_1

 

1) Two plants (snapdragon) with red flowers and white flowers are crossed and the following results are shown: 

 

i) What phenomenon is shown in F1 generation?

 

ii) Write the genotype of F1 and phenotype of F2 generation.

 

iii) What is the phenotypic and genotypic ratio of the F2 generation?

 

iv) With the help of a punnet square illustrate the result.
ANSWER: Principles Of Inheritance And Variation
Ans1) IAi ,   IBi  , AB, ii
 
Ans 2 ) It is a back cross. The genotype of yellow seed is Yy.
 
3 Marks
 
1) The trait is autosomal dominant. The dark circle character is on autosomal dominant character in the heterozygous condition. The progeny is 1:1
CBSE_Class_12_Biology_Inheritance_Variation_Ans_1
3. i)More the recombination frequency percentage more recombinants varieties..ii) linkage.
 
5 Marks
 
1.i) Incomplete dominance.
 
ii) Genotype F1 = Rr
    Genotype F2 = 1RR : 2 Rr : 1rr
iii) Phenotypic ratio Red : Pink : White
1 : 2 : 1
CBSE_Class_12_Biology_Inheritance_Variation_Ans_3
2 Rr-Pink
1 rr-White
 
iv) F1 Rr X rr 1 RR- Red
CBSE_Class_12_Biology_Inheritance_Variation_Ans_2
 
 
Important Questions for NCERT Class 12 Biology Principles of Inheritance and Variation
 

Ques. The genotype of a plant showing the dominant phenotype can be determined by
(a) test cross
(b) dihybrid cross
(c) pedigree analysis
(d) back cross. 

Answer: A

Ques. Which one of the following cannot be explained on the basis of Mendel’s law of dominance?
(a) The discrete unit controlling a particular character is called a factor.
(b) Out of one pair of factors one is dominant, and the other recessive.
(c) Alleles do not show any blending and both the characters recover as such in F2 generation.
(d) Factors occur in pairs. 

Answer: C

Ques. ABO blood grouping is controlled by gene I which has three alleles and show co-dominance. There are six genotypes. How many phenotypes in all are possible?
(a) Six
(b) Three
(c) Four
(d) Five

Answer: C

Ques. A cross in which an organism showing a dominant phenotype is crossed with the recessive parent in order to know its genotype is called
(a) monohybrid cross
(b) back cross
(c) test cross
(d) dihybrid cross.

Answer: C

Ques. In Antirrhinum two plants with pink flowers were hybridized. The F1 plants produced red, pink and white flowers in the proportion of 1 red, 2 pink and 1 white. What could be the genotype of the two plants used for hybridisation? Red flower colour is determined by RR and white by rr genes.
(a) rrrr   
(b) RR
(c) Rr     
(d) rr 

Answer: C

Ques. In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with a green seeded plant, what ratio of yellow and green seeded plants would you expect in F1 generation?
(a) 9 : 1
(b) 1 : 3
(c) 3 : 1
(d) 50 : 50 

Answer: D

Ques. A common test to find the genotype of a hybrid is by
(a) crossing of one F2 progeny with female parent
(b) studying the sexual behaviour of F1 progenies
(c) crossing of one F1 progeny with male parent
(d) crossing of one F2 progeny with male parent.

Answer: C

Ques. Test cross involves
(a) crossing between two genotypes with dominant trait
(b) crossing between two genotypes with recessive trait
(c) crossing between two F1 hybrids
(d) crossing the F1 hybrid with a double recessive genotype. 

Answer: D

Ques. Phenotype of an organism is the result of
(a) genotype and environment interactions
(b) mutations and linkages
(c) cytoplasmic effects and nutrition
(d) environmental changes and sexual dimorphism.

Answer: A

Ques. A gene is said to be dominant if
(a) it expresses its effect only in homozygous state
(b) it expresses its effect only in heterozygous condition
(c) it expresses its effect both in homozygous and heterozygous condition
(d) it never expresses its effect in any condition.

Answer: C

Ques. When dominant and recessive alleles express itself together it is called
(a) co-dominance
(b) dominance
(c) amphidominance
(d) pseudodominance.

Answer: A

Ques. In hybridisation, Tt × tt gives rise to the progeny of ratio
(a) 2 : 1
(b) 1 : 2 : 1
(c) 1 : 1
(d) 1 : 2. 

Answer: C

Ques. A child’s blood group is ‘O’. The parent’s blood groups cannot be
(a) A and B
(b) A and A
(c) AB and O
(d) B and O.

Answer: C

Ques. A child of O-group has B-group father. The genotype of father will be
(a) IOIO
(b) IBIB
(c) IAIB
(d) IBIO. 

Answer: D

Ques. An allele is dominant if it is expressed in
(a) both homozygous and heterozygous states
(b) second generation
(c) heterozygous combination
(d) homozygous combination. 

Answer: A

Ques. An organism with two identical alleles is
(a) dominant
(b) hybrid
(c) heterozygous
(d) homozygous. 

Answer: D

Ques. A man of A-blood group marries a woman of AB blood group. Which type of progeny would indicate that man is heterozygous A?
(a) AB
(b) A
(c) O
(d) B 

Answer: D

Ques. Multiple alleles control inheritance of
(a) phenylketonuria
(b) colour blindness
(c) sickle cell anaemia
(d) blood groups. 

Answer: D

Ques. The contrasting pairs of factors in Mendelian crosses are called
(a) multiple alleles
(b) allelomorphs
(c) alloloci
(d) paramorphs. 

Answer: C

Ques. Mendel’s last law is
(a) segregation
(b) dominance
(c) independent assortment
(d) polygenic inheritance. 

Answer: A

Ques. Blue eye colour is recessive to brown eye colour. A brown eyed man whose mother was blue eyed marries a blue-eyed woman. The children will be
(a) both blue eyed and brown eyed 1 : 1
(b) all brown eyed
(c) all blue eyed
(d) blue eyed and brown eyed 3 : 1. 

Answer: A

Ques. RR (Red) Antirrhinum is crossed with white (WW) one. Offspring RW are pink. This is an example of
(a) dominant-recessive
(b) incomplete dominance
(c) hybrid
(d) supplementary genes. 

Answer: B

Ques. ABO blood group system is due to
(a) multifactor inheritance
(b) incomplete dominance
(c) multiple allelism
(d) epistasis. 

Answer: C

Ques. tt mates with Tt. What will be characteristic of offspring?
(a) 75% recessive
(b) 50% recessive
(c) 25% recessive
(d) All dominant

Answer: B

Chapter 01 Reproduction in Organisms
CBSE Class 12 Biology HOTs Reproduction In Organisms
Chapter 02 Sexual Reproduction In Flowering Plants
CBSE Class 12 Biology HOTs Sexual Reproduction In Flowering Plants
Chapter 03 Human Reproduction
CBSE Class 12 Biology HOTs Human Reproduction
Chapter 04 Reproductive Health
CBSE Class 12 Biology HOTs Reproductive Health
Chapter 05 Principles of Inheritance and Variation
CBSE Class 12 Biology HOTs Principles Of Inheritance And Variation
Chapter 06 Molecular Basis of Inheritance
CBSE Class 12 Biology HOTs Molecular Basis of Inheritance
Chapter 08 Human Health and Disease
CBSE Class 12 Biology HOTs Human Health and Disease
Chapter 09 Strategies for Enhancement In Food Production
CBSE Class 12 Biology HOTs Strategies For Enhancement In food Production
Chapter 10 Microbes In Human Welfare
CBSE Class 12 Biology HOTs Microbes In Human Welfare
Chapter 11 Biotechnology Principles and Processes
CBSE Class 12 Biology HOTs Biotechnology Principles and Processes
Chapter 12 Biotechnology and Its Application
CBSE Class 12 Biology HOTs Biotechnology And Its Applications
Chapter 13 Organisms and Populations
CBSE Class 12 Biology HOTs Organism And Population
Chapter 15 Biodiversity and Conservation
CBSE Class 12 Biology HOTs Biodiversity And Conservation
Chapter 16 Environmental Issues
CBSE Class 12 Biology HOTs Environmental Issues

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CBSE Class 12 Biology Chapter 5 Principles of Inheritance and Variation HOTS

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HOTS for Biology CBSE Class 12 Chapter 5 Principles of Inheritance and Variation

Expert teachers of studiestoday have referred to NCERT book for Class 12 Biology to develop the Biology Class 12 HOTS. If you download HOTS with answers for the above chapter daily, you will get higher and better marks in Class 12 test and exams in the current year as you will be able to have stronger understanding of all concepts. Daily High Order Thinking Skills questions practice of Biology and its study material will help students to have stronger understanding of all concepts and also make them expert on all critical topics. You can easily download and save all HOTS for Class 12 Biology also from www.studiestoday.com without paying anything in Pdf format. After solving the questions given in the HOTS which have been developed as per latest course books also refer to the NCERT solutions for Class 12 Biology designed by our teachers

Chapter 5 Principles of Inheritance and Variation HOTS Biology CBSE Class 12

All HOTS given above for Class 12 Biology have been made as per the latest syllabus and books issued for the current academic year. The students of Class 12 can refer to the answers which have been also provided by our teachers for all HOTS of Biology so that you are able to solve the questions and then compare your answers with the solutions provided by us. We have also provided lot of MCQ questions for Class 12 Biology in the HOTS so that you can solve questions relating to all topics given in each chapter. All study material for Class 12 Biology students have been given on studiestoday.

Chapter 5 Principles of Inheritance and Variation CBSE Class 12 HOTS Biology

Regular HOTS practice helps to gain more practice in solving questions to obtain a more comprehensive understanding of Chapter 5 Principles of Inheritance and Variation concepts. HOTS play an important role in developing an understanding of Chapter 5 Principles of Inheritance and Variation in CBSE Class 12. Students can download and save or print all the HOTS, printable assignments, and practice sheets of the above chapter in Class 12 Biology in Pdf format from studiestoday. You can print or read them online on your computer or mobile or any other device. After solving these you should also refer to Class 12 Biology MCQ Test for the same chapter

CBSE HOTS Biology Class 12 Chapter 5 Principles of Inheritance and Variation

CBSE Class 12 Biology best textbooks have been used for writing the problems given in the above HOTS. If you have tests coming up then you should revise all concepts relating to Chapter 5 Principles of Inheritance and Variation and then take out print of the above HOTS and attempt all problems. We have also provided a lot of other HOTS for Class 12 Biology which you can use to further make yourself better in Biology.

Where can I download latest CBSE HOTS for Class 12 Biology Chapter 5 Principles of Inheritance and Variation

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Yes, the HOTS issued by CBSE for Class 12 Biology Chapter 5 Principles of Inheritance and Variation have been made available here for latest academic session

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What does HOTS stand for in Class 12 Biology Chapter 5 Principles of Inheritance and Variation

HOTS stands for "Higher Order Thinking Skills" in Chapter 5 Principles of Inheritance and Variation Class 12 Biology. It refers to questions that require critical thinking, analysis, and application of knowledge

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Yes, HOTS questions are important for Chapter 5 Principles of Inheritance and Variation Class 12 Biology exams as it helps to assess your ability to think critically, apply concepts, and display understanding of the subject.